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There are 5 burglars and once went to a bakery to rob it
obviously The first guy ate 1/2 of the total bread and 1/2
of the bread. The second guy ate 1/2 of the remaining and
1/2 of the bread. The third guy ,fourth guy and fifth guy
did the same. After fifth guy there is no bread left out.
How many bread are there?
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Answer Posted / guest
let the total no of breads be x.
1st man 2nd man
x- (x/2) - 1/2 - 1/2((x-1)/2) - 1/2 ..... so on.
ans is 31.
first ate : 15.5 + .5 = 16 remaining 15
second ate : 7.5+0.5 = 8 remaining 7.
third ate : 3.5 +0.5 = 4 remaining 3.
fourth ate : 1.5 + 0.5 = 2 remaining 1
fifth ate : 0.5 + 0.5 = 1 remaining 0
| Is This Answer Correct ? | 7 Yes | 0 No |
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