A program that will create a movie seat reservation. The program will display the summary seats and its status. The user will be ask what seat no. to be reserved, then it will go back again to the summary to display the updated seat status. If the seat no. is already reserved then it will prompt an error message. And also if the input seat no is out of range then it will also prompt an error message. The program is continuously running. Termination of the program will depends on how the programmer will apply. Sample output: Movie Seats Reservation Summary of Seats: Seat 1: Available Seat 2: Available Seat 3: Available Seat 4: Available Seat 5: Available Enter seat no. (Press 0 to terminate Or the assigned seat capacity) : 1 Movie Seats Reservation Summary of Seats: Seat 1: Reserve Seat 2: Available Seat 3: Available Seat 4: Available Seat 5: Available Enter seat no. (Press 0 to terminate Or the assigned seat capacity) : 6 The Seat no. is out of range! Movie Seats Reservation Summary of Seats: Seat 1: Reserve Seat 2: Available Seat 3: Available Seat 4: Available Seat 5: Available Enter seat no. (Press 0 to terminate Or the assigned seat capacity) : 1 The Seat no. is already reserved! Movie Seats Reservation Summary of Seats: Seat 1: Reserve Seat 2: Available Seat 3: Available Seat 4: Available Seat 5: Available Enter seat no. (Press 0 to terminate Or the assigned seat capacity) : 0 GoodBye... Thank You!!!

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How to access command-line arguments?

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main() { int i=5; printf("%d%d%d%d%d%d",i++,i--,++i,--i,i); }

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#define FALSE -1 #define TRUE 1 #define NULL 0 main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); }

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main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); } int i;

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main() { int i=5,j=6,z; printf("%d",i+++j); }

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int aaa() {printf(“Hi”);} int bbb(){printf(“hello”);} iny ccc(){printf(“bye”);} main() { int ( * ptr[3]) (); ptr[0] = aaa; ptr[1] = bbb; ptr[2] =ccc; ptr[2](); }

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prog. to produce 1 2 3 4 5 6 7 8 9 10

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Given a list of numbers ( fixed list) Now given any other list, how can you efficiently find out if there is any element in the second list that is an element of the first list (fixed list)

3 Answers   Disney, Google, ZS Associates,

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#include <stdio.h> #define a 10 main() { #define a 50 printf("%d",a); }

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main() { int i=-1; -i; printf("i = %d, -i = %d \n",i,-i); }

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Print an integer using only putchar. Try doing it without using extra storage.

2 Answers  

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