hello sir,is there any function in C that can calculate number
of digits in an int type variable,suppose:int a=123;
3 digits in a.what ll b answer?
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Answer / muni
I am sorry the previous answer is for different question.
For your question the answer is ver simple.
use sprintf and strlen.
char str[10];
sprintf(str,"%d",number)
number of digits = strlen(str);
| Is This Answer Correct ? | 10 Yes | 1 No |
Answer / ramesh
int countDigits(number)
{
if (number==0)
return 0;
else
return 1 + countDigits(number%10);
}
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / devendra
Answer #2 is right we can also use atoi() and itoa() function.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / arti sharma
void main()
{ int num,i,count=0;
printf("enter a no");
scanf("%d",&num);
while(num!=0)
{ count=count+1;
i=num%10;
num=num/10;
}
printf("count=%d",count);
getch();
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sreejesh1987
Small change to Ramesh's answer.
I got answer when i done like this.
int countDigits(number)
{
if (number==0)
return 0;
else
return 1 + countDigits(number/10);//change % to /
}
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / muni
There is no function to calculate the number of bits. But
there is a very simple logic for calculating it.
int count = 0;
While( num!=0 )
{
count++;
num = num & (num-1);
}
| Is This Answer Correct ? | 1 Yes | 9 No |
main() { int i = 257; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }
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