How to identify the object has compiled with the debug view as
*source without using STRDBG?

Answers were Sorted based on User's Feedback



How to identify the object has compiled with the debug view as *source without using STRDBG?..

Answer / grcsreddy

Use DSPPGM (PGM name) --> command and then press enter 2
times you can get/see Debug data: *YES ,that means the
source complied with *source

Is This Answer Correct ?    7 Yes 2 No

How to identify the object has compiled with the debug view as *source without using STRDBG?..

Answer / john

Debug Data *yes can be seen on the 3rd screen of dsppgm is you are displaying all data.
Put 5 on the module and just do one page down

Is This Answer Correct ?    4 Yes 2 No

How to identify the object has compiled with the debug view as *source without using STRDBG?..

Answer / ankit taneja

I did not find such kind of option....

Is This Answer Correct ?    4 Yes 3 No

How to identify the object has compiled with the debug view as *source without using STRDBG?..

Answer / sandeep

In DSPPGM there is not such any option to find.

Is This Answer Correct ?    4 Yes 4 No

How to identify the object has compiled with the debug view as *source without using STRDBG?..

Answer / srikanth

If program is compiled with DBGVIEW *NONE, Then DEBUG DATA will be *NO, in rest of all cases it DEBUG DATA *YES even it is compiled with *SOURCE, *STMT, *LIST

Is This Answer Correct ?    3 Yes 3 No

How to identify the object has compiled with the debug view as *source without using STRDBG?..

Answer / san

Using DSPPGM Command and option Debug data: *YES, u can
find out the object has been compiled with Debug mode with
*source or not.

Is This Answer Correct ?    5 Yes 7 No

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