Answer / gabbar

a="ABCD EBCF GBCH IBCJ"
b=Split(a," ")
For i=LBound(b) to UBound(b)
msgbox "count: "&i&" "& mid(b(i),2,2)
Next

Answer / koteswar

str = " ABCD EBCF GBCH IBCJ HERE I NET"
n = split(str, "BC")
cnt = ubound (n)
msgbox cnt

Answer / snegha

ar2=Array("ABCD","EBCF","GBCH","IBCJ")


arlen=UBound(ar2)-lbound(ar2)+1 'Finding array length

For p= 0 to arlen-1
msgbox Mid(ar2(p),2,3)
Next

Answer / dinesh1433

Dim AR2,i

AR2=Array("ABCD","EBCF","GBCH","IBCJ")

For i=0 to ubound(AR2)
If (Instr(AR2(i),"BC")<>0) Then
msgbox "BC found in Element :"&AR2(i)
End If

Next

Answer / rajesh

hai.. Koteswar
i need to say thanks for your quick reply ..
but my question is how to get BC IN A ARRAY means i need to
display it.....,BUT YOU ANS THAT HOW MANY BC ARE THERE IN
THE ARRAY LIST .....IF POSSIBLE PLEASE GIVE A COMMANDS AGAIN...

Answer / pushkar1206

This will print BC 4 times.

a="ABCD EBCF GBCH IBCJ"
b=Split(a," ")
For i=0 to ubound(b)
msgbox mid(b(i),2,2)
Next

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