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THERE IS A SQUARE ABCD. A LINE AF IS DRAWN FROM THE POINT A
TO POINT F WHICH LIES ON THE LINE OF THE SQUARE BC AND
ANOTHER LINE DE IS DRAWN FROM THE POINT D TO POINT E WHICH
LIES ON THE LINE OF THE SQUARE AB. THE LINE DE AND AF
INTERSECT AT O. IT IS GIVEN THAT AE AND BF ARE EQUAL AND AO
IS 4cm AND AE IS 5cm. FIND EO.
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Answer / bikram
apply pythagorous theorum on triangle AEO.
AE being Hypotenues.
it is bcz angle at A has reduced by same amount as has increased at E.
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Answer / bikram
Triangle AEO is a right angle triangle with AE being hypotenues.
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