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How to swap two variables, without using third variable ?
Answers were Sorted based on User's Feedback
Answer / yogendra
a=5
a=5,b=10
a=a+b
a=10+5=15
a=15
b=a-b
b=15-10
b=5
a=a-b
a=15-5
a=10 and b=5
a=10 and b=5
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / praveen kumar kesani
x=10,y=20;
x=x*y;
y=x/y;
x=x/y;
after swapping : x=20,y=10
| Is This Answer Correct ? | 2 Yes | 5 No |
Answer / ruchi
let the two numbers are a & b
a=a+b
b=a-b
a=a-b
let a=5 & b=10
a=a+b=15
b=a-b=15-10=5
b=5
a=a-b=15-5=10
hence a & b become 10 & 5
| Is This Answer Correct ? | 0 Yes | 3 No |
Answer / balusamy
Try this answer for reverse a string
#include<stdio.h>
void main()
{
char array[50] = "thgir si rewsna ym";
int len,i,j,temp;
len = strlen(array);
for(i = 0, j = len - 1; i < j; i++, j--)
{
temp = array[i];
array[i] = array[j];
array[j] = temp;
}
printf("%s\n",array);
}
| Is This Answer Correct ? | 0 Yes | 4 No |
Answer / smita
suppose a=5 and b=10
a=a*b ==>a=50
b=a/b ==>b=5;
a=a/b ==>a=10;
| Is This Answer Correct ? | 1 Yes | 5 No |
Answer / ashok
The first two answers are correct. Third will FAIL in the
case the second num is 0...Please do not post wrong answer
| Is This Answer Correct ? | 3 Yes | 8 No |
Answer / some guy
declare a fourth variable and use that.
I dont understand why you need to do any of the above ??? if fourth is a problem, declare fifth and so on...
| Is This Answer Correct ? | 2 Yes | 7 No |
Answer / robince kumar
//C++ code..
void main()
{
int number1,number2;
cout<<"Enter 1st number;
cin>>number1;
cout<<"Enter 2nd number;
cin>>number2;
number1=number1*number2;
number2=number1/number2;
number1=number1/number2;
getch();
}
| Is This Answer Correct ? | 0 Yes | 6 No |
¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...
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2 Answers CTS, Microsoft, ViPrak,
#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s; printf("%d",s->x); printf("%s",s->name); }
main() { char *str1="abcd"; char str2[]="abcd"; printf("%d %d %d",sizeof(str1),sizeof(str2),sizeof("abcd")); }
write a program in c to merge two array
1. const char *a; 2. char* const a; 3. char const *a; -Differentiate the above declarations.
int swap(int *a,int *b) { *a=*a+*b;*b=*a-*b;*a=*a-*b; } main() { int x=10,y=20; swap(&x,&y); printf("x= %d y = %d\n",x,y); }
C Code 
