Answer / mohit prakash saxena

Yes IT is absolutely correct

Answer / yogendra

a=5
a=5,b=10

a=a+b
a=10+5=15
a=15
b=a-b
b=15-10
b=5


a=a-b
a=15-5
a=10 and b=5


a=10 and b=5

Answer / praveen kumar kesani

x=10,y=20;
x=x*y;
y=x/y;
x=x/y;

after swapping : x=20,y=10

Answer / ruchi

let the two numbers are a & b

a=a+b
b=a-b
a=a-b

let a=5 & b=10
a=a+b=15
b=a-b=15-10=5
b=5

a=a-b=15-5=10
hence a & b become 10 & 5

Answer / balusamy

Try this answer for reverse a string


#include<stdio.h>
void main()
{
char array[50] = "thgir si rewsna ym";
int len,i,j,temp;

len = strlen(array);

for(i = 0, j = len - 1; i < j; i++, j--)
{
temp = array[i];
array[i] = array[j];
array[j] = temp;
}

printf("%s\n",array);
}

Answer / smita

suppose a=5 and b=10
a=a*b ==>a=50
b=a/b ==>b=5;
a=a/b ==>a=10;

Answer / ashok

The first two answers are correct. Third will FAIL in the
case the second num is 0...Please do not post wrong answer

Answer / sonya

first & third answers are correct.

Answer / some guy

declare a fourth variable and use that.
I dont understand why you need to do any of the above ??? if fourth is a problem, declare fifth and so on...

Answer / robince kumar

//C++ code..
void main()
{
int number1,number2;
cout<<"Enter 1st number;
cin>>number1;
cout<<"Enter 2nd number;
cin>>number2;
number1=number1*number2;
number2=number1/number2;
number1=number1/number2;
getch();
}

int swap(int *a,int *b) { *a=*a+*b;*b=*a-*b;*a=*a-*b; } main() { int x=10,y=20; swap(&x,&y); printf("x= %d y = %d\n",x,y); }

1 Answers  

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2 Answers  

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Write a c program to search an element in an array using recursion

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