Answer / deepjot kaur

void AddTwoNumbers();
#pragma startup AddTwoNumbers

void main()
{
printf("\n Executing Main...");
}


void AddTwoNumbers()
{
int num1,num2 = 0;
printf( "\nEnter number 1 : ");
scanf( "%d", &num1 );

printf( "\nEnter number 2 : ");
scanf( "%d", &num2 );

printf( "\nThe sum is = %d..." ,(num1 + num2) );
}

Answer / boss

Answer#1 above by Deepjot Kaur is the ONLY CORRECT ANSWER
Here. Pls ignore all others. They Posters did not understood
the Question basically.

The Qn is: We need to write a program in which there is one
main and a function. When executed, Function should run
first and then the Main().

Answer / sheenu

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c;
clrscr();
printf("enter the value");
scanf("%d%d",&a,&b);
c=a+b;
printf("%d",c);
getch();
}

Answer / govind verma

but #prgma does not support on gcc... so this code is run only turbo c ......

Answer / naveen

#include <stdio.h>
#include <conio.h>
void main();
{

int a,b,c;
scanf("%d%d", &a,&b);
printf("enter a two numbers \n");
c=a+b;
printf("The add of two numbers are %d ",c);
clrscr();
getch();
}

Answer / salini

#include<stdio.h>
void main()
{
int a,b,c;
printf("Enter the first number :");
scanf("%d \n",&a);
printf("Enter the second number :");
scanf("%d \n",&b);
c=a+b;
printf("The addition of %d and %d is %d",&a,&b,&c);
}

Answer / pavan mustyala

#include <stdio.h>

int func()
{
int a = 10;
int b = 20;
printf("\nExecuting func FIRST...\n");

printf("Sum of the two numbers is %d", (a + b));
return (a + b);
}

int x = func();

int main(int argc, char* argv[])
{
printf("\nExecuting Main LAST...\n");
return 0;
}

Answer / nirmal bhattarai

#include<stdio.h>
#include<conio.h>
void main()
{
rintf("\n Executing Main...");
}


void AddTwoNumbers()
{
int num1,num2 = 0;
printf( "\nEnter number 1 : ");
scanf( "%d", &num1 );

printf( "\nEnter number 2 : ");
scanf( "%d", &num2 );

printf( "\nThe sum is = %d..." ,(num1 + num2) );
}
get();
}

Answer / b.vinod

#include<stdio.h>
main()
{
int a,b,c;
printf("Enter the value a,b");
scanf("%d%d",&a,&b);
c=a+b;
printf("c value is%d",a);
}

Answer / divya prabhu

#include<stdio.h>
#include<conio.h>

void add()
{
int a,b,c;
printf("\n Enter the two numbers to be added:");
scanf("%d %d",&a,&b);
c=a+b;
printf("\n The addition of two entered numbers is: %
d",c);
}


void main()
{
clrscr();
add();
getch();
}

void main () { int x = 10; printf ("x = %d, y = %d", x,--x++); } a. 10, 10 b. 10, 9 c. 10, 11 d. none of the above

2 Answers   HCL,

How do you write a program which produces its own source code as its output?

7 Answers  

main() { int (*functable[2])(char *format, ...) ={printf, scanf}; int i = 100; (*functable[0])("%d", i); (*functable[1])("%d", i); (*functable[1])("%d", i); (*functable[0])("%d", &i); } a. 100, Runtime error. b. 100, Random number, Random number, Random number. c. Compile error d. 100, Random number

1 Answers   HCL, rsystems,

write a c program to Create a mail account by taking the username, password, confirm password, secret_question, secret_answer and phone number. Allow users to register, login and reset password(based on secret question). Display the user accounts and their details .

2 Answers  

#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s; printf("%d",s->x); printf("%s",s->name); }

3 Answers   Hexaware,

Link list in reverse order.

8 Answers   NetApp,

main() { int i = 257; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }

1 Answers   CSC,

Sir... please give some important coding questions asked by product companies..

0 Answers  

main() { int i=5,j=10; i=i&=j&&10; printf("%d %d",i,j); }

1 Answers  

main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); }

1 Answers  

main() { char string[]="Hello World"; display(string); } void display(char *string) { printf("%s",string); }

2 Answers   Wipro,

struct aaa{ struct aaa *prev; int i; struct aaa *next; }; main() { struct aaa abc,def,ghi,jkl; int x=100; abc.i=0;abc.prev=&jkl; abc.next=&def; def.i=1;def.prev=&abc;def.next=&ghi; ghi.i=2;ghi.prev=&def; ghi.next=&jkl; jkl.i=3;jkl.prev=&ghi;jkl.next=&abc; x=abc.next->next->prev->next->i; printf("%d",x); }

1 Answers