5 tables and 10 chairs were sold for 20000.15%gain for
table,10%loss on chair.overall profit rs
750.the cp of table is
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let CP of 1 table be x and chair be y
SP of table = 5.75x, SP of chair=9Y
Given that total profit is Rs.750 thus 9y+5.75x-5x-10y=750 eqn 1
also 5x+10y=20000
on solving both equations we get
x=2200
i.e. cost of one table is Rs.2200
| Is This Answer Correct ? | 9 Yes | 1 No |
Answer / arunav
5(1.15x) + 10(0.9y) =20000
5.75x + 9y =20000
and
5(0.15x) -10(0.1y) =750
0.75x -y =750
9(0.75x -y) =9*750
Solve two :
CP of one table is 2140
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / sangram
1.15x+.9y=20000;
0.15x-.1y=750;
solving above eqn,
x=10700
| Is This Answer Correct ? | 2 Yes | 3 No |
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