Answer / unknown

#include<stdio.h>

void main()
{
int i,j,k,num = 5;

for(i = num;i > 0;i--){
for(j = 1;j <= i;j++){
printf(" ");
}
for(k = (j - 1);k < num;k++){
if(k==j-1 || k==num-1)
printf("*");
else
printf(" ");
printf(" ");
}
printf(" \n");
}


for(i = num;i > 0;i--){
for(j = (num - i);j > 0;j--){
printf(" ");
}
for(k = 0;k < i;k++){
if(k==0|| k==i-1)
printf("*");
else
printf(" ");
printf(" ");
}
printf(" \n");
}
}

what is run time error?

7 Answers  

---

Given that two int variables, total and amount , have been declared, write a sequence of statements that: initializes total to 0 reads three values into amount , one at a time. After each value is read in to amount , it is added to the value in total (that is, total is incremented by the value in amount ). Instructor's notes: If you use a loop, it must be a for loop. And if you use a loop control variable for counting, you must declare it.

1 Answers   Google,

---

Write a C program to enter 10 integer numbers through one variable and count how many of them are even using while loop ?

2 Answers  

---

Write a c-programe that input one number of four digits and find digits sum?

2 Answers  

---

what is the large sustained error signal that eventually cause the controller output to drive to its limit

1 Answers   TCS,

---

how tally is useful?

2 Answers  

---

quoroum of computer languages?

0 Answers   Infosys,

---

Given that two int variables, total and amount, have been declared, write a loop that reads integers into amount and adds all the non-negative values into total. The loop terminates when a value less than 0 is read into amount. Don't forget to initialize total to 0. Instructor's notes: This problem requires either a while or a do-while loop.

3 Answers  

---

which typw of errors ? & how to solve it ?

0 Answers  

---

void main() { int i=7; printf("N= %*d",i,i); }

6 Answers   HCL,

---

what is syntax error?

3 Answers  

---

write the value of x and y after execution of the statements: int x=19,y; y=x++ + ++x; x++; y++;

0 Answers  

---