Answer / unknown

#include<stdio.h>

void main()
{
int i,j,k,num = 5;

for(i = num;i > 0;i--){
for(j = 1;j <= i;j++){
printf(" ");
}
for(k = (j - 1);k < num;k++){
if(k==j-1 || k==num-1)
printf("*");
else
printf(" ");
printf(" ");
}
printf(" \n");
}


for(i = num;i > 0;i--){
for(j = (num - i);j > 0;j--){
printf(" ");
}
for(k = 0;k < i;k++){
if(k==0|| k==i-1)
printf("*");
else
printf(" ");
printf(" ");
}
printf(" \n");
}
}

wap for bubble sort

3 Answers  

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Using string functions write a program that will accept the name of the capital as input value and will display the corresponding country. ------------------------ Capitals Countries ------------------------ Capitals Countries Ottawa Canada Moscow Russia Rome Italy I can't not get it to run properly

1 Answers   AMA,

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Given an int variable n that has already been declared and initialized to a positive value, and another int variable j that has already been declared, use a do...while loop to print a single line consisting of n asterisks. Thus if n contains 5, five asterisks will be printed. Use no variables other than n and j .

2 Answers  

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Declaration of Cube Guys please help me.. Is this a right way to declare cube.? If i Compile it. It Says: Cube undeclared what should i do? Please help \thanks in advanced #include<stdio.h> #include<math.h> #include<conio.h> main( ) { float x,y; while(x++<10.0) { printf("Enter Number:"); scanf("%d", &x); y = cube(x); printf("%f %f %f \n", x,pow(x,2),y); cube(x); } { float x; float y; y = x*x*x; } getch(); return (y); }

2 Answers  

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void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?

24 Answers   HCL,

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what are the techniques for reducing the fragility of a memory bug?

1 Answers  

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What is the code for following o/p * * * * * * * * * * * * * * * *

1 Answers  

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how to convert decimal to hexadecimal without using arrays just loops

2 Answers  

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Why are memory errors hard to debug?

1 Answers  

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How to upgrade LOOP environment, I just mean, how can i make loop statement editable ? I just try some program using loop statement and checking it in multiple compilers. Every compiler showing different output, what's the wrong ? is it a compiler based problem, or loop based problem, tell me why ? and what will be the debugging process, for this kind of problem ?

1 Answers  

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#include"stdio.h" #include"conio.h" void main() { int a; printf("\n enter a number:"); scanf("%c\n"); getch(); }

12 Answers   HCL,

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Assume that the int variables i and j have been declared, and that n has been declared and initialized. Write code that causes a "triangle" of asterisks of size n to be output to the screen. Specifically, n lines should be printed out, the first consisting of a single asterisk, the second consisting of two asterisks, the third consistings of three, etc. The last line should consist of n asterisks. Thus, for example, if n has value 3, the output of your code should be * ** *** You should not output any space characters. Hint: Use a for loop nested inside another for loop.

2 Answers   HCL,

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