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#include<>stdio.h>
#include<>conio.h>
{
printf("hello");
void main()
getch();
} what the out put of this program and why ......plz clear
my answer
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Answers were Sorted based on User's Feedback
Answer / sambath
answer is =" Unable to open the header files and must be
open brash come after main program "
| Is This Answer Correct ? | 18 Yes | 5 No |
Answer / meg&
#include<stdio.h>
#include<conio.h>
voidn main
{
clrscr();
printf("Try this one");
getch();
}
| Is This Answer Correct ? | 9 Yes | 4 No |
Answer / naina
#include<stdio.h>
#include<conio.h>
void main()
{
printf("any message to display on console");
getch();
}
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / lalithpriya
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
printf("Hello!");
getch();
}
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / sansiri
the output is not display for this program because unable to
open header files due to the syntax is error and after the
main function only the braces are opened
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / dhatchina moorthy
actually this program will be showing error
the correct one may be following:
#include<>stdio.h>
#include<>conio.h>
void main()
{
printf("hello");
getch();
}
| Is This Answer Correct ? | 5 Yes | 7 No |
Answer / geetha.s.b
answer is =" Unable to open the header files and must be
open brash come after main program "
| Is This Answer Correct ? | 0 Yes | 5 No |
Answer / shreyas
#include<stdio.h>
#include<conio.h>
{
printf("hello");
void main()
getch();
}
if this is the case....then it will return an error that
braces '{' are not at the right place
| Is This Answer Correct ? | 4 Yes | 10 No |
Answer / parvathy mohan
#include<>stdio.h>
#include<>conio.h>
void main()
{
printf("hello");
scanf("%d",&hello);
getch();
}
| Is This Answer Correct ? | 0 Yes | 6 No |
void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?
Given that two int variables, total and amount, have been declared, write a loop that reads integers into amount and adds all the non-negative values into total. The loop terminates when a value less than 0 is read into amount. Don't forget to initialize total to 0. Instructor's notes: This problem requires either a while or a do-while loop.
#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }
Write a program to accept two strings of Odd lengths. Then take all odd characters from one string and even characters from the other and concatenate and produce a string.
wap for bubble sort
printy(a=3,a=2)
what is meant for variable not found?
void main() { int i=5,y=3,z=2,ans; clrscr(); printf("%d",++i + --z + i++ + --i * ++y); i=5,y=3,z=2; ans=++i + --z + i++ + --i * ++y; printf("\n%d",ans); getch(); } Its output is 37 and 31.... Please explain me why its different How it works.....
what are the techniques for reducing the fragility of a memory bug?
void main() { int i=5; printf("%d",i+++++i); }
Declaration of Cube Guys please help me.. Is this a right way to declare cube.? If i Compile it. It Says: Cube undeclared what should i do? Please help \thanks in advanced #include<stdio.h> #include<math.h> #include<conio.h> main( ) { float x,y; while(x++<10.0) { printf("Enter Number:"); scanf("%d", &x); y = cube(x); printf("%f %f %f \n", x,pow(x,2),y); cube(x); } { float x; float y; y = x*x*x; } getch(); return (y); }
how tally is useful?
C C++ Errors 
