Interested to Buy Any Domain ? << Click Here >> for more details...
Given that two int variables, total and amount, have been
declared, write a loop that reads integers into amount and
adds all the non-negative values into total. The loop
terminates when a value less than 0 is read into amount.
Don't forget to initialize total to 0.
Instructor's notes: This problem requires either a while or
a do-while loop.
- 3 Answers
- 30686 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / helen
total=0;
cin>>amount;
while (amount>=0)
{
total=total+amount;
cin>>amount;
}
| Is This Answer Correct ? | 43 Yes | 20 No |
Answer / cammy pope
total=0;
cin>>amount;
total= total+amount;
cin>>amount;
total= total+amount;
cin>>amount;
total= total+amount;
| Is This Answer Correct ? | 10 Yes | 13 No |
Answer / abhishek rajput
int total=0, amount;
scanf("%d",&amount);
while(amount>0)
{
total=total+amount;
scanf("%d",&amount);
}
printf("total=%d",total);
| Is This Answer Correct ? | 1 Yes | 5 No |
void main() { int i=5; printf("%d",i+++++i); }
Answering Yes or No in C++...using only stdio.h and conio.h..........help me please...? here's must be the output of the program: Screen A Exam No. items Score 1 20 20 2 35 35 Another Entry? [Y] or [N] : Screen B: Record No. Student's Name: 1 Fernando Torres 2 Chuck Norris Note: if you press Y, the program must repeat the procedure in screen A, then if N, the program must proceed to the screen B....Please Help me out............
2. A student studying Information Technology at Polytechnic of Namibia is examined by coursework and written examination. Both components of assessment carry a maximum of 50 marks. The following rules are used by examiners in order to pass or fail students. a. A student must score a total of 40% or more in order to pass (total = coursework marks + examination marks) b. A total mark of 39% is moderated to 40% c. Each component must be passed with a minimum mark of 20/50. If a student scores a total of 40% or more but does not achieve the minimum mark in either component he/she is given a technical fail of 39% (this mark is not moderated to 40%) d. Grades are awarded on marks that fall into the following categories. Mark 100-70 69-60 59-50 49-40 39-0 Grade A B C D E Write a program to input the marks for both components (coursework marks out of 50 and examination marks out of 50), out put the final mark and grade after any moderation. [30]
UINT i,j; i = j = 0; i = ( i++ > ++j ) ? i++ : i--; explain pls....
char* f() return "hello:"; void main() {char *str=f(); }
Assume that the int variables i and j have been declared, and that n has been declared and initialized. Write code that causes a "triangle" of asterisks of size n to be output to the screen. Specifically, n lines should be printed out, the first consisting of a single asterisk, the second consisting of two asterisks, the third consistings of three, etc. The last line should consist of n asterisks. Thus, for example, if n has value 3, the output of your code should be * ** *** You should not output any space characters. Hint: Use a for loop nested inside another for loop.
class test { int a; public: test(int b):a(b){} void show(){ cout<<a; } }; void main() { test t1; test t2(5); t1.show(); t2.show(); } }
void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?
what is meant for variable not found?
How to convert hexadecimal to binary using c language..
1 Answers Bajaj, GAIL, Satyam, Zenqa,
A sample program using data structure? what is file handling?
I am using Qt 5.6 during compilation it stops and gives error about Qmake The process "C:QtQt5.6.35.6.3msvc2015_64inqmake.exe" crashed. Error while building/deploying project untitled1 (kit: Desktop Qt 5.6.3 MSVC2015 64bit) When executing step "qmake"
C C++ Errors 
