write a program in c language to get the value of arroy
keys pressed and display the message which arrow key is
pressed?
Answer / mohamed ziavudeen
#define KBHOME 327
#define KBEND 335
#define KBUP 328
#define KBDOWN 336
#define KBPGUP 329
#define KBPGDN 337
#define KBLEFT 331
#define KBINS 338
#define KBRIGHT 333
#define KBDEL 339
c0 = getch();
if (c0==0) {
c1=getch()+256;
if (c1==KBUP)
{
printf("You had hit the upper arrow key");
else if (c1==KBDOWN)
printf("You had hit the DOWN arrow key");
else if (c1==KBLEFT)
printf("You had hit the LEFT arrow key");
else if(c1==KBRIGHT)
printf("You had hit the RIGHT arrow key");
else
printf("You had hit some other key");
}
}
Is This Answer Correct ? | 1 Yes | 2 No |
#define a 10 int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } void foo() { #undef a #define a 50 }
#define int char main() { int i=65; printf("sizeof(i)=%d",sizeof(i)); }
Is the following code legal? struct a { int x; struct a b; }
main() { char c=' ',x,convert(z); getc(c); if((c>='a') && (c<='z')) x=convert(c); printf("%c",x); } convert(z) { return z-32; }
main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }
#define assert(cond) if(!(cond)) \ (fprintf(stderr, "assertion failed: %s, file %s, line %d \n",#cond,\ __FILE__,__LINE__), abort()) void main() { int i = 10; if(i==0) assert(i < 100); else printf("This statement becomes else for if in assert macro"); }
What is full form of PEPSI
respected sir, i did my MCA in 2013 when i am going to attend to an interview i was asked about my project how will i explain my project could please help me in this and my project title is "Social Networking Site For Social Responsibility"
main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); }
find A^B using Recursive function
#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }
main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit = (bit >> (i - (i -1)))); } } a. 512, 256, 128, 64, 32 b. 256, 128, 64, 32, 16 c. 128, 64, 32, 16, 8 d. 64, 32, 16, 8, 4