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One train leaves Los Angeles at 15mph heading for New York.
Another train leaves from New York at 20mph heading for Los
Angeles on the same track. If a bird, flying at 25mph,
leaves from Los Angeles at the same time as the train and
flies back and forth between the two trains until they
collide, how far will the bird have traveled?
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Answer / pc
lolz.
idiots trying to provide "cool" sounding and apparently complicated, though senseless answers.
firstly, the bird travels faster than both trains, so the bird will at least make one u turn. this is for the dude who said above that the bird will make only one way trip.
For the answer:
The trains are travelling in opposite directions, so consider one train stationary and the other one will appear moving at 15 + 20 = 35 miles/hr.
Bird is moving at 25 miles/hr.
Given the info that the bird will keep flying till the crash happens the ratio of the speeds of the train in motion and the bird's speed is equal to the ratio of the distance travelled by them.
So 35 (trains speed) / 25 (birds speed) = X (distance between LA & NY) / Y (Distance travelled by train.
So Y = (25/35)*X = 0.714 X where X is unknown in the problem statement
Now shut up everyone.
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / shishir
1st solution is correct but it has to take x distance
between NY and LA ,cz we wont take any distance unless or
until data is not provided.
so i think solution would be 5/7th distance
of,distance between NY and LA.
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / @!3
consider dist b/w LA & NY 2 b 100m.
suppose the trains collide at a pt. A.
it tks same time 4 both da trains 2 reach A.
they will collide at a dist of:
x/15=(100-x)/20
x=42.86
so, the bird,no mater how many trips it made b/w LA n NY,end
of da day it wuld have travelled 42.86% of the distance
startin 4m LA.
| Is This Answer Correct ? | 6 Yes | 9 No |
Answer / capt. savem
you guys are reading to much into it the answer is for the
person to say that they don't know instead of trying to
figure a solution for a problem they don't have all the
details for as you would if you were given a job to do but
didn't have any instructions what would your do? Ask for
some more info.
and if the trains are barreling down the track at a
combines speed of 35 MPH the bird would only be able to
make one trip.
| Is This Answer Correct ? | 2 Yes | 5 No |
Answer / vikash
The answer is more than half distance btw LA and NW ...
| Is This Answer Correct ? | 1 Yes | 5 No |
Answer / sam spade
Assuming the New York train leaves the same time as the Los
Angeles train and the bird, the answer is
5X/12 miles where X is the length of the track in miles.
Since work has to be shown:
[(x mi / 15 mph) - (x mi / 20mph)] = T hours, the amount of
time until the trains crash.
T hours * 25 mph = D miles, the distance the bird can
travel before the trains crash.
Combining the equations will give the answer.
Additionally, as the trains approach each other, the bird
will travel an infinite number of shorter and shorter trips
between the trains.
| Is This Answer Correct ? | 1 Yes | 6 No |
Answer / bharath
Some of the answers are acceptable but a more accurate
solution is available :
If the distance is specified find the distances traveled by
the bird on the first three trips , these distances will
form some mathematical series , which can be used to find
the distances in the future trips .
PS: It forms a series only if the problem is framed with a
appropriate distance.
| Is This Answer Correct ? | 0 Yes | 6 No |
Answer / randy
Who Cares. It's a stupid question for an interview anyway.
Like one of those Who's burried in Grant's tomb...Irrelevent
| Is This Answer Correct ? | 1 Yes | 8 No |
Answer / dumbo
Why would the bird want to fly between the trains? Let it go anywhere it wants and we would have this problem to be solved.
| Is This Answer Correct ? | 5 Yes | 15 No |
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