Please let know the scripts for counting number of repeated
letters in the word. Note repeated letter should not be
count agian.
Ex: If "Hello" is my word... l is coming twice.. it should
count once and print... secong 'l' should not count again..
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Answer / vishala
An optimised code with one loop:
strsting = "HelLo"
strnew = ""
For i = 1 To Len(strsting)
If InStr(1, strnew, Mid(strsting, i, 1), vbTextCompare) = 0 Then
strnew = Mid(strsting, i, 1) & strnew
strarr = Split(strsting, Mid(strsting, i, 1), -1, vbTextCompare)
If UBound(strarr) > 1 Then
MsgBox Mid(strsting, i, 1) & " is repeated " & _
UBound(strarr) & "times"
End If
End If
Next
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / chaitanya
Option Explicit
Dim st,cnt,str,i,j
str = "happy"
For i=1 to len(str)
cnt =0
st = mid(str,i,1)
For j=1 to len(str)
If mid(str,j,1)=st Then
cnt =cnt +1
End If
Next
If cnt>1Then
msgbox st & " repeats " & cnt & "times"
End If
Next
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / mahesh.k
str=inputbox("enter a string")
ln=len(str)
nr=0
cnt=0
For i=1 to ln
If cnt>0 Then
nr=nr+1
End If
cnt=0
If strcomp(x,mid(str,i,1))<>0 Then
For j=i+1 to ln
If mid(str,i,1)=mid(str,j,1) then
cnt=cnt+1
x=mid(str,i,1)
end if
next
else
i=i+1
End If
Next
msgbox "no.of repeeted charecters="&nr
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sunil
A="Hello"
Set rxp = New RegExp
With rxp
.Global = True
.IgnoreCase = True
.Pattern ="l"
End With
Set colMatch = rxp.Execute(A)
msgbox colMatch.count
| Is This Answer Correct ? | 2 Yes | 2 No |
Dim str,ln,i,md,ub,sp
str="apple"
ln=len(str)
for i=1 to ln
md=mid(str,i,1)
sp=split(str,md)
ub=ubound(sp)
if ub=i+1 then
msgbox md &vbnewline& "contain more than one character in
given string"
else
msgbox md &vbnewline& "contain only one character in given
string"
end if
next
If any modifications are there please let me know....
| Is This Answer Correct ? | 1 Yes | 2 No |
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