#include<stdio.h>
int main()
{ int i=0,j=1,k=2,m,n=0;
m=i++&&j++&&k++||n++;
printf("%d,%d,%d,%d,%d",i,j,k,m,n);
}
Answers were Sorted based on User's Feedback
Answer / g krishna rao
1,1,2,0,1
when it encounters zero it will not check remaining conditions
and go to or conditions and incriment n
Is This Answer Correct ? | 3 Yes | 2 No |
Answer / manish soni tagore collage jai
m=i++&&j++&&k++||n++;
in this expression
first
m=0++&&...........
from rule of && opr c1&&c2
if c1 is 0(FLASE) it don't chacke the next expression
so
m=0---------------(1);
after this
m=i++&&j++&&k++||n++;
-----------------------
m=i++&&j++&&k++ is flase so only i is increase by and j and
k not effect.
-------------------------------
after that
in ||(OR )OPR
C1||C2
IF C1 IS 0(FALSE) THEN IT CHECK THE C2
m=i++&&j++&&k++(C1)||n++(C2);
THEN C1 IS 0 and c2 is 0++ is 1 so true.
so answer is
1,same,same,0,i,
Is This Answer Correct ? | 4 Yes | 4 No |
Answer / kishore krishnan.s.r
Its actually a doubt
Since ++ has high precidence than && will it not be evaluated first.
then ans will be 1,2,3,0,1
Is This Answer Correct ? | 0 Yes | 1 No |
What character terminates all strings composed of character arrays? 1) 0 2) . 3) END
i want to switch my career from quailty assurance engineering to development kindly guide me from which programming language its better for me to start plz refer some courses or certifications too i have an experience of 1.5 yrs in QA field.Kindly guide me
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