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#include<stdio.h>
int main()
{ int i=0,j=1,k=2,m,n=0;
m=i++&&j++&&k++||n++;
printf("%d,%d,%d,%d,%d",i,j,k,m,n);
}
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Answer Posted / manish soni tagore collage jai
m=i++&&j++&&k++||n++;
in this expression
first
m=0++&&...........
from rule of && opr c1&&c2
if c1 is 0(FLASE) it don't chacke the next expression
so
m=0---------------(1);
after this
m=i++&&j++&&k++||n++;
-----------------------
m=i++&&j++&&k++ is flase so only i is increase by and j and
k not effect.
-------------------------------
after that
in ||(OR )OPR
C1||C2
IF C1 IS 0(FALSE) THEN IT CHECK THE C2
m=i++&&j++&&k++(C1)||n++(C2);
THEN C1 IS 0 and c2 is 0++ is 1 so true.
so answer is
1,same,same,0,i,
| Is This Answer Correct ? | 4 Yes | 4 No |
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