WIPRO PLACEMENT PAPERS ---------- Placement Paper 3

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> Wipro paper(System software)

>
> PART --A
> ------------------------------------------------------
> 1) abcD+abcd+aBCd+aBCD
> then the simplified function is
> ( Capital letters are copliments of corresponding
letters
> A=compliment of a)
>
> [a] a [b] ab [c] abc [d] a(bc)* [e] mone
> (bc)*=compliment of bc
>
> Ans: e
>
> -------------------------------------
> 2) A 12 address lines maps to the memory of
>
> [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none
>
> Ans: b
>
> ----------------------------------------
> 3) In a processor these are 120 instructions . Bits
needed to impliment
> this instructions
> [a] 6 [b] 7 [c] 10 [d] none
>
> Ans: b
>
> -----------------------------------------
> 4) In 8085 microprocessor READY signal does.which of the
following
> is incorrect statements
> [a]It is input to the microprocessor
> [b] It sequences the instructions
>
> Ans : b
> ----------------------------------------
>
> 5) Return address will be returned by function to
> [a] Pushes to the stack by call
> Ans : a
> ------------------------------------------
> 6)
> n=7623
> {
> temp=n/10;
> result=temp*10+ result;
> n=n/10
> }
>
> Ans : 3267
> ----------------------------------------------
> 7) If A>B then
> F=F(G);
> else B>C then
> F=G(G);
> in this , for 75% times A>B and 25% times B>C then,is
10000 instructions
> are there ,then the ratio of F to G
> [a] 7500:2500 [b] 7500:625 [c] 7500:625 if a=b=c
else
> 7500:2500

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> --------------------------------------------------
> > int zap(int n)
> {
> if(n<=1)then zap=1;
> else zap=zap(n-3)+zap(n-1);
> }
> then the call zap(6) gives the values of zap
> [a] 8 [b] 9 [c] 6 [d] 12 [e] 15
>
> Ans: b
> ----------------------------------------------------------
-----
>
>
> PART-B
> -------
> 1) Virtual memory size depends on
> [a] address lines [b] data bus
> [c] disc space [d] a & c [e] none
>
> Ans : a
> -----------------------------------------------
> 2) Critical section is
> [a]
> [b] statements which are accessing shared resourses
> Ans : b
> -------------------------------------------------
>
> 3) load a
> mul a
> store t1
> load b
> mul b
> store t2
> mul t2
> add t1
>
> then the content in accumulator is
>
> Ans : a**2+b**4
> ---------------------------------------------------
> 4) question (3) in old paper
> 5) q(4) in old paper
> 6) question (7) in old paper
> 7) q(9) in old paper
> ------------------------------
>

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