Answer / sagai

boolean isPalindrome(string s){
char[] letters = s.toCharArray() //convert string to
array of characters
int firstCnt = 0 //counter for left side
int secCnt = letters.length - 1 //counter for right
side
while (firstCnt < secCnt){ //work toward middle
if (letters[firstCnt] != letters[secCnt]){
return false //if left and right does not
match, is not a palindrome
}
firstCnt++
secCnt--
}
return true //if loop completes without a false, is a
palinrome
}

Answer / nandan_101

boolean isPalindrome(string s){
char[] letters = s.toCharArray() //convert string to
array of characters
int firstCnt = 0 //counter for left side
int secCnt = letters.length - 1 //counter for right
side
while (firstCnt < secCnt){ //work toward middle
if (letters[firstCnt] != letters[secCnt]){
return false //if left and right does not
match, is not a palindrome
}
}
return true //if loop completes without a false, is a
palinrome
}boolean isPalindrome(string s){
char[] letters = s.toCharArray() //convert string
<strong class="highlight">to</strong> array of characters
int firstCnt = 0 //counter for left side
int secCnt = letters.length - 1 //counter for right
side
while (firstCnt < secCnt){ //work toward middle
if (letters[firstCnt] != letters[secCnt]){
return false //if left and right does not
match, is not a <strong
class="highlight">palindrome</strong>
}
}
return true //if loop completes without a false, is a
palinrome
}

can u give me the sample bug report

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