How we print the table of 2 using for loop in c
programing?
Answers were Sorted based on User's Feedback
Answer / anil kumar nahak
#include<stdio.h>
#include<conio.h>
void main()
{
int num=2,r;
clrscr();
printf("\n The Table Of Number Two \n");
for(r=1;r<=10;r++)
{
printf("\n %d * %d = %d",num,r,num*r);
}
getch();
}
| Is This Answer Correct ? | 333 Yes | 93 No |
Answer / shruthi
int i,result;
for(i=1;i<=10;i++)
{
result=i*2;
printf("%d\n",result);
}
| Is This Answer Correct ? | 174 Yes | 58 No |
Answer / hemendra singh gurjar
#include<stdio.h>
#include<conio.h>
void main()
{
int r;
clrscr();
printf("\n The Table Of Number Two \n");
for(r=1;r<=10;r++)
{
printf("\n%d",r*2);
}
getch();
}
| Is This Answer Correct ? | 79 Yes | 23 No |
Answer / jitender singh
#include<stdio.h>
#include<conio.h>
Void main()
{
Int r;
Clrscr();
Printf("\n The table of Number Two \n");
for(r=1;r<=10;r++)
{
printf("\n%d",r*2);
}
getch();
}
| Is This Answer Correct ? | 44 Yes | 20 No |
Answer / vaibhav
int i,result;
for(i=1;i<=10;i++)
{
result=i*2;
printf("%d\n",result);
}
| Is This Answer Correct ? | 36 Yes | 26 No |
Answer / mohib ullah orakzai
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int a=2,b;
for(int c=1;c<=10;c++)
{
b=a*c;
cout<<a<<"*"<<c<<"="<<b<<endl;
}
getch();
}
| Is This Answer Correct ? | 24 Yes | 15 No |
Answer / laxmi kanth
#include<stdio.h>
main()
{
int a,n;
printf("/nenter the table:\n");
scanf("%d",&a);
for(n=1;n<=10;n++)
printf("\nthe table is:\n%d*%d=%d,a,n,a*n);
}
| Is This Answer Correct ? | 18 Yes | 13 No |
Answer / naresh
#include<stdio.h>
int main(void)
{
int a=2,c;
for(c=1;c<=10;c++)
{
printf("%4d",a*c);
}
return 0;
}
| Is This Answer Correct ? | 12 Yes | 7 No |
Answer / aik expert
<?php
for ($a=0; $a<=10; $a++)
{
$b=$a*3;
echo "3*$a=$b<br>";
}
?>
| Is This Answer Correct ? | 1 Yes | 0 No |
main() { int x=5; clrscr(); for(;x<= 0;x--) { printf("x=%d ", x--); } } a. 5, 3, 1 b. 5, 2, 1, c. 5, 3, 1, -1, 3 d. –3, -1, 1, 3, 5
func(a,b) int a,b; { return( a= (a==b) ); } main() { int process(),func(); printf("The value of process is %d !\n ",process(func,3,6)); } process(pf,val1,val2) int (*pf) (); int val1,val2; { return((*pf) (val1,val2)); }
#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }
main( ) { char *q; int j; for (j=0; j<3; j++) scanf(“%s” ,(q+j)); for (j=0; j<3; j++) printf(“%c” ,*(q+j)); for (j=0; j<3; j++) printf(“%s” ,(q+j)); }
void main() { int i=10, j=2; int *ip= &i, *jp = &j; int k = *ip/*jp; printf(“%d”,k); }
#define clrscr() 100 main() { clrscr(); printf("%d\n",clrscr()); }
String reverse with time complexity of n/2 with out using temporary variable.
int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().
What is the hidden bug with the following statement? assert(val++ != 0);
Is the following code legal? typedef struct a { int x; aType *b; }aType
What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }
Write a single line c expression to delete a,b,c from aabbcc