Answer / anil kumar nahak

#include<stdio.h>
#include<conio.h>
void main()
{
int num=2,r;
clrscr();
printf("\n The Table Of Number Two \n");
for(r=1;r<=10;r++)
{
printf("\n %d * %d = %d",num,r,num*r);
}
getch();
}

Answer / shruthi

int i,result;

for(i=1;i<=10;i++)
{
result=i*2;
printf("%d\n",result);
}

Answer / hemendra singh gurjar

#include<stdio.h>
#include<conio.h>
void main()
{
int r;
clrscr();
printf("\n The Table Of Number Two \n");
for(r=1;r<=10;r++)
{
printf("\n%d",r*2);
}
getch();
}

Answer / jitender singh

#include<stdio.h>
#include<conio.h>
Void main()
{
Int r;
Clrscr();
Printf("\n The table of Number Two \n");
for(r=1;r<=10;r++)
{
printf("\n%d",r*2);
}
getch();
}

Answer / vaibhav

int i,result;

for(i=1;i<=10;i++)
{
result=i*2;
printf("%d\n",result);
}

Answer / mohib ullah orakzai

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int a=2,b;
for(int c=1;c<=10;c++)
{
b=a*c;
cout<<a<<"*"<<c<<"="<<b<<endl;
}
getch();
}

Answer / laxmi kanth

#include<stdio.h>
main()
{
int a,n;
printf("/nenter the table:\n");
scanf("%d",&a);
for(n=1;n<=10;n++)
printf("\nthe table is:\n%d*%d=%d,a,n,a*n);
}

Answer / naresh

#include<stdio.h>
int main(void)
{
int a=2,c;
for(c=1;c<=10;c++)
{
printf("%4d",a*c);
}
return 0;
}

Answer / dipankar kumar

Yes

Answer / aik expert

<?php
for ($a=0; $a<=10; $a++)
{
$b=$a*3;
echo "3*$a=$b<br>";

}
?>

Write a C program to add two numbers before the main function is called.

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1 Answers