what happens if power factor is maintained at 0.9?give me
the answer in technicall way rather than telling the
penality n all
Answers were Sorted based on User's Feedback
Answer / guest
See the first thing is Power factor is angle between
voltage & current. see most of our load is inductive, & in
inductive load current always lags the supply voltage. In
unity P.f.condition current & voltage always in phase with
each other.
since P=VIcos(angle between V & I )
Now for a constant power as your pf changes i.e. decreases
to keep power demand constant current has to be increase as
your voltage is constant.in this way your current
increases , it causes increase in your copper losses
(I*I*R), voltage drop(I*R). And to keep voltage constant
more reactive power has to be provide.
generally any supply company penalties for more demand of
reactive power.
Is This Answer Correct ? | 11 Yes | 4 No |
Answer / neo
The relation between the KW and KVA are
KW = KVA*Cos(phi)...SO as the power factor is getting lower
the actual outptut that we obtain frm a transformer will be
lower than the desired output for a particular value of
vlotage and current in that circuit.That is why in
industries, much importance in given for power factor
improvement.
Is This Answer Correct ? | 4 Yes | 1 No |
Answer / hirosh babu
kw=kvacos(phi)... so larger the value of pf, smaller is the
amount of kva required for supplying active power... for
example if we require 8kw power output and pf is0.8 kva req
is 10.. but if pf is 0.5 kva req is 16... also for
transfering a const power if pf is low,... then value of
current will be high , so cu loss increases so does the
size of conductor..
Is This Answer Correct ? | 3 Yes | 0 No |
Answer / hirosh babu
All the above answers are right. I just want to add few
points to that.
For transmitting a const power,
lower the power factor, greater will be the current and
hence greater will be losses and larger area of cross
section of conductor will be required.
By maintaining pf at 0.9, our active power will be high as
P= VI cos (pi), larger the pf larger the active power for a
fixed voltage and current.
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / badri narayan satpathy
If the power factor is .9 then we get a power loss.
Because power = volatse*current*cos phi(active power)
there for we also paid tha bill including the losses and
the losses is an usefullpower.power factor depend on the
type load like
inductive
capacitive
resitive
Is This Answer Correct ? | 0 Yes | 1 No |
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