Answer / gaurang bhavsar- jr. asst. ele

Elect. Power(3-ph)=1.732*V*I*p.f.Now,
2h.p.=2*0.746=1.492=1.5 kw. So, If a voltage system of 3-
ph,415V, 50 Hz is taken, assuming a p.f. of 0.8 then--
1.5=1.732*0.415*I*0.8 which gives I=2.6085 Amp of normal
current. The starting current will be approx. 3 times of
normal current i.e.-7.82 Amp.

Answer / kanchan mukherjee

p=1.732*v*i*.8
p=2hp=1.5kw
v=415
1.5*1000=1.732*415*i*.8
i=1500/1.732*415*.8
i=2.7 amp.

Answer / rajagopal

2Hp=1492Watts

I=1.732x415x0.8 =575.024

575.024/1492=0.38540482
0.385x1000 =3.85

Answer / rajasekar.a

3.85

Which modulation has higher data rates a.fm b.am c.qam d.qpsk

1 Answers   NTDC,

---

i have flexible wire. size of conductors is 0.190 mm & no.of conductors are 48. then size of wire comes 1.37 sqmm instead of 1.5 sqmm . the what is tolerance for this size.

0 Answers  

---

Why HT voltages are expressed in 11KV,22KV,33KV and so on? (ie in times of 11)

3 Answers   Bhel, Park Hotel,

---

why all selected supply voltage are multiple of 11

1 Answers   Gamesa, Suzlon,

---

why the neutral of power transformer is always earthed?

1 Answers  

---

how to flameproof electrical motor on the shaft?

0 Answers  

---

How we can calculate the life of Lead acid battery

0 Answers   ABC,

---

distribution is maximum done by a)radial b)network c) parallel d)b & c

0 Answers  

---

If the capacitor bank is installed in switchyard say 132/22kv then on LT side say 22kv/0.433kv is it necessary to install capacitor bank for maintaining power factor. if pf is maintained on HT side then will that be maintained on LT side as well.if not then how&why??????/ please explain...........

3 Answers   MacLellan,

---

Transformer type...??

1 Answers  

---

The moisture in air will condense at

0 Answers   Caterpillar,

---

For electrical designers what are the standard should know? i want learn about this standards. how to get information/reference. anybody help in this regards please.

0 Answers  

---