Answer / rohit

Yes i can provide u with the complete project.

Answer / ankur

thanx buddy but how could u provide me that and how could i
contact u......well my email id is
access_ankur@rediffmail.com...........
if u desire than u can send me a project on this email id or
tell me anyway by which i could approach you.

I am currently doing my btech in computer science in Coimbatore.I had intererest to do btech in chemical enginerring but couldnt get a seat. Now what are my options ,scope and future if i take mtech in chemical enginerring? And can i apply for any deemed colleges for mtech chemical enginerring through gate taking my present state into consideration(btech in cse and mtech in chemical enginerring)

0 Answers  

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can you explain about the design calculations and procedure of boiler

0 Answers   Reliance,

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PROCESS CONTROL - EXAMPLE 6.2 : A stream with volumetric flow rate Q enters a cylindrical tank and a stream with volumetric flow rate q exits the tank. The fluid has a constant heat capacity and density. There is no temperature change or chemical reaction occurring in the tank. Develop a model for determining the height of the tank, h. Let V is the volume, A is the cross sectional area, r is the density, m is the mass, where V and A are for the tank, r and m are for the fluid. The rate of mass of fluid accumulation, dm / dt = (Q - q) r. Prove the model to be dh / dt = (Q - q) / A.

1 Answers  

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I HAVE DOMAIN KNOWLEDGE IN PROCESS MANUFACTURINGAND I GOT AN APPARTUNITY AS A BUSINESS ANALYST AND I DNT HAVE ANY KNOWLEDGE ON ORACLE APPS/GIVE ME ANY VALUBLE SUGGESTION?

0 Answers   Satyam,

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What are some common methods for helium leak testing a vacuum system?

0 Answers  

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Jspl question paper for freshers requirements chemical engineering diploma

0 Answers  

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DIFFERENTIAL EQUATIONS - EXAMPLE 20.1 : By using Excel program either on laptop or desktop PC, solve the differential equation dy / dx = -2y + x + 4 with h = 0.005, initial values : x = 0, y = 1. The 4th order Runge-Kutta method provides : y(N + 1) = y(N) + (1/6) (k1 + 2k2 +2k3 + k4), k1 = h [ -2y(N) + x(N) + 4 ], k2 = h { -2 [ y(N) + k1 / 2 ] + x(N) + h / 2 + 4 }, k3 = h { -2 [ y(N) + k2 / 2 ] + x(N) + h / 2 + 4 }, k4 = h { -2 [ y(N) + k3 ] + x(N) + h + 4 }. What is the value of y at x = 0.5?

1 Answers  

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is extractive distillationӞH

0 Answers  

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What are some good tank mixing rules of thumb?

0 Answers  

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Dielectric materials in static fields

0 Answers   HCL,

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What are the types of clarifier used in water treatement plant?

1 Answers   Adani,

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what is defferance between tubular & automotive plate battery

0 Answers  

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