PROCESS DESIGN - EXAMPLE 21.3 : According to a heuristic of chemical engineering

PROCESS DESIGN - EXAMPLE 21.3 : According to a heuristic of chemical engineering plant design, assume a pressure difference dP = 4 psi for each 10-ft rise in elevation. A pump is needed to pump liquid from a storage tank at a lower elevation to a heating tank at a higher elevation with the elevation difference of 60 ft. (a) Find the pressure loss due to such elevation. (b) If the required minimum inlet pressure to the heating tank is 9 psi, with 1 control valve is installed between pump and heating tank, what is the dP minimum required for the control valve and the entrance to the heating tank when the heuristic mentions that at least 10 psi is required for the control valve? (c) The pressure at the inlet of the pump is 8 psi and the flowrate of the liquid produces pressure head of 50 psi. What is the total pressure produced by the pump? (d) Assume a pipeline dP of 2 psi / 100 ft for liquid flow in a pipe according to heuristic, what is the approximate maximum length of the pipe in ft that can be installed between the pump and the heating tank?

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PROCESS DESIGN - EXAMPLE 21.3 : According to a heuristic of chemical engineering plant design, assum..

Answer / kangchuentat

PROCESS DESIGN - ANSWER 21.3 : (a) dP = (4 psi / 10 ft) x 60 ft = 24 psi. (b) dP = 9 + 10 = 19 psi minimum. (c) P of pump = 8 + 50 = 58 psi. (d) dP for pipe = Answer of (c) - Answer of (a) - Answer of (b) = 58 - 24 - 19 = 15 psi. Maximum length of pipe = (100 ft / 2 psi) x 15 psi = 750 feet. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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