Question 8 - A local utility burns coal having the following composition on a dr

Question 8 - A local utility burns coal having the following composition on a dry basis : Carbon (C) 83.05 %, hydrogen (H) 4.45 %, oxygen (O) 3.36 %, nitrogen (N) 1.08 %, sulfur (S) 0.7 % and ash 7.36 %. Calculate the ash free composition of the coal with reference to C, H, O, N and S.

Question Posted / kang chuen tat

1 Answers
4671 Views
I also Faced
E-Mail Answers

Question 8 - A local utility burns coal having the following composition on a dry basis : Carbon (C)..

Answer / kang chuen tat

Answer 8 - Total percentage without ash is 83.05 + 4.45 + 3.36 + 1.08 + 0.7 = 92.64 %. For ash free composition percentage calculations, C = 83.05 / 92.64 x 100 % = 89.65 %. H = 4.45 / 92.64 x 100 % = 4.80 %. O = 3.36 / 92.64 x 100 % = 3.63 %. N = 1.08 / 92.64 x 100 % = 1.17 %. S = 0.7 / 92.64 x 100 % = 0.76 %. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

Is This Answer Correct ?

5 Yes

2 No

Post New Answer

More Chemical Engineering Interview Questions

Why should a magnesium ribbon be cleaned before burning in air?

0 Answers

In case of welded vessels why is stress relieving in the form of post-weld treatment necessary?

0 Answers

hi.i m student of chemical engg. and studying in 5 th sem.how can i improve my technical knowledge..can u sugest me a link like book or any website..?

3 Answers

What step should be taken in process industries if the process variable is oscillating?

0 Answers HPCL,

What are the assumptions made for kynch theory?

0 Answers

What are demand of crotonaldehyde99% in the worldand its international market ?

0 Answers

QUANTUM COMPUTING - EXAMPLE 32.7 : If | ± > = 0.707 ( | 0 > ± | 1 > ), prove that | Ψ (t = 0) > = | 0 > = 0.707 ( | + > + | - > ).

1 Answers

Chemical Engineering Unit Operation - Which of the sequence below represent a feasible flows of ethanol processing plants using cellulose as starting material? A. raw material --> heat exchanger --> distillation column --> reactor. B. reactor --> distillation column --> raw material --> heat exchanger. C. heat exchanger --> raw material --> distillation column --> reactor. D. raw material --> heat exchanger --> reactor --> distillation column. E. distillation column --> raw material --> reactor --> heat exchanger.

1 Answers

pls send me model paper of NPCIL for executive trainee. and syllabus of executive trainee 2015.

0 Answers

what is meant by runaway temperature in a reactor?

3 Answers Cairn,

Can anyone help me to find out the book where all chemical engineer problem is solved.

3 Answers

Explain the factors involved in considering the choice of dry screw compressor?

0 Answers

For more Chemical Engineering Interview Questions Click Here