main() { int y=10; if(y++>9 && y++!=10 && y++>10)

main()
{
int y=10;
if(y++>9 && y++!=10 && y++>10)
{
printf("%d",y);
else
printf("%d",y);
}
}

Question Posted / him

4 Answers
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main() { int y=10; if(y++>9 && y++!=10 && y++>10) { printf("..

Answer / jane

Is This Answer Correct ?

11 Yes

2 No

main() { int y=10; if(y++>9 && y++!=10 && y++>10) { printf("..

Answer / yash golwara

answer will be 13 but we need to first need to edit the code it has some errors
so could be this
#include<stdio.h>
#include<conio.h>
main()
{
int y=10;
if(y++>9 && y++!=10 && y++>10)
{
printf("%d",y);
}
else
printf("%d",y);
}

so now it will give answer 13 in each process it svalues increases and three process so it will increase to 13

Is This Answer Correct ?

4 Yes

2 No

main() { int y=10; if(y++>9 && y++!=10 && y++>10) { printf("..

Answer / shruthi

Is This Answer Correct ?

2 Yes

2 No

main() { int y=10; if(y++>9 && y++!=10 && y++>10) { printf("..

Answer / nagendra kumar

Is This Answer Correct ?

3 Yes

7 No

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