Answer / best in the world

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
{
printf("%d ",(i+j+1)%2);
}
printf("\n");
}
getch();
}




THIS IS THE BEST SOLUTION IN THE WORLD

Answer / suket

Mine doesn't require 3 variables:
#include<stdio.h>
int main()
{
int i,j,rows;
printf("Enter no. of rows: ");
scanf("%d",&rows);

printf("Here's your pattern: \n");
for (i=1;i<=rows;i++)
{
for(j=i;j!=0;)
{
if(j%2==0)
{
printf("01");
j=j-2;
}
else
{
printf("1");
j--;
}
}
printf("\n");
}
return 0;
}

Answer / guriya kumari

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
{
if(i%2==0)
{
if(j%2==0)
{
k=1;
printf("%d",k);
}
else
{
k=0;
printf("%d",k);
}
}
else
{
if(j%2==0)
{
k=0;
printf("%d",k);
}
else
{
k=1;
printf("%d",k);
}
}
}
printf("\n");
}
}

Answer / krishna anil dadge

#include<iostream>
using namespace std;
int main()
{
for(int i=1;i<=5;i++)
{
for(int j=1;j<=i;j++)
{
if((i+j)%2==0)
{
cout<<"1";
}
else
{
cout<<"0";
}
}
cout<<endl;
}
return 0;
}

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