in 33kv line how much current will be
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Example.
power is 2000 kva
Then p=√3 v*i *cosΦ
I=p/√3 v*cosΦ,2000/1.732*33*0.8
I=2000/45.7248,
I=43.74 Amps
| Is This Answer Correct ? | 12 Yes | 5 No |
Answer / ramesh behera
The value of current depends upon with certification
I= P/V
i=V/R
or i= √p/r
here V=33kv
Kva= kv*a
kva=kv*1.732*i
Power = Volts * Amps.
i=P/V
i= kva / kv*1.732
if kva= 1250
so 1250/57.156=22A
Just mail me -ramesh.behera66@yahoo.in
| Is This Answer Correct ? | 1 Yes | 7 No |
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