Answer / susie

Answer :

Compier Error: '&' on register variable

Rule to Remember:

& (address of ) operator cannot be applied on register
variables.

Answer / chandra

It all depends on C/C++.

On C(GNU C/Visual studio C compiler), it will get a compiler
error.
since the keyword with register is stored in registers of
CPU rather than in memory locations of RAM.

On C++(GNU C++/Visual stdio C++ compiler), variable 'a' will
get an address of memory locations.
since register will automatically take address of memory

Answer / shrikantauti

Will produce an error as the memory address s not provided.
%u should had written instead of %d

‎#define good bad main() { int good=1; int bad=0; printf ("good is:%d",good); }

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How we will connect multiple client ? (without using fork,thread)

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Cau u say the output....?

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2 Answers  

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There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }

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#include<stdio.h> main() { int i=1,j=2; switch(i) { case 1: printf("GOOD"); break; case j: printf("BAD"); break; } }

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What is the output for the following program main() { int arr2D[3][3]; printf("%d\n", ((arr2D==* arr2D)&&(* arr2D == arr2D[0])) ); }

1 Answers  

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