Answer / susie

Answer :

1

Explanation:

Note the semicolon after the while statement. When the value
of i becomes 0 it comes out of while loop. Due to
post-increment on i the value of i while printing is 1.

void main() { int *i = 0x400; // i points to the address 400 *i = 0; // set the value of memory location pointed by i; }

2 Answers  

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#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

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4 Answers   Google, HCL, Quick Heal, WTF,

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what is the output of the below program & why ? #include<stdio.h> void main() { int a=10,b=20,c=30; printf("%d",scanf("%d%d%d",&a,&b,&c)); }

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main() { char *str1="abcd"; char str2[]="abcd"; printf("%d %d %d",sizeof(str1),sizeof(str2),sizeof("abcd")); }

1 Answers  

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how to concatenate the two strings

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3 Answers  

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abcdedcba abc cba ab ba a a

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Is the following code legal? typedef struct a { int x; aType *b; }aType

1 Answers  

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