main()
{
char *p = “ayqm”;
printf(“%c”,++*(p++));
}
Answers were Sorted based on User's Feedback
Answer / ravneet kaur
as *p has address of a.and after increment p++ it moves to
y and after ++*(p++) its address is incremented and gets the
another location and gets the value z and value of memory
location is any other value.
| Is This Answer Correct ? | 6 Yes | 14 No |
char inputString[100] = {0}; To get string input from the keyboard which one of the following is better? 1) gets(inputString) 2) fgets(inputString, sizeof(inputString), fp)
How to access command-line arguments?
main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }
What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }
plz send me all data structure related programs
3) Int Matrix of certain size was given, We had few valu= es in it like this. =97=97=97=97=97=97=97=97=97=97=97 1 = | 4 | | 5 | &= nbsp; | 45 =97=97=97=97=97=97=97=97=97=97=97 &n= bsp; | 3 | 3 | 5 | = | 4 =97=97=97=97=97=97=97=97=97=97=97 34 |&nbs= p; 3 | 3 | | 12 | &= nbsp; =97=97=97=97=97=97=97=97=97=97=97 3 | &nbs= p; | 3 | 4 | = | 3 =97=97=97=97=97=97=97=97=97=97=97 3 | = ; | | | = ; 3 | =97=97=97=97=97=97=97=97=97=97=97 &= nbsp; | | 4 | = ; | 4 | 3 We w= ere supposed to move back all the spaces in it at the end. Note: = If implemented this prog using recursion, would get higher preference.
Given a list of numbers ( fixed list) Now given any other list, how can you efficiently find out if there is any element in the second list that is an element of the first list (fixed list)
3 Answers Disney, Google, ZS Associates,
main() { static int var = 5; printf("%d ",var--); if(var) main(); }
main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }
Is the following code legal? typedef struct a { int x; aType *b; }aType
char *someFun() { char *temp = “string constant"; return temp; } int main() { puts(someFun()); }
main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }