Answer / susie

Answer :

100

Explanation:

Preprocessor executes as a seperate pass before
the execution of the compiler. So textual replacement of
clrscr() to 100 occurs.The input program to compiler looks
like this :

main()

{

100;

printf("%d\n",100);

}

Note:

100; is an executable statement but with no
action. So it doesn't give any problem

Answer / naveen

yes it works and prints 100 because we defined clrscr() to
100. we can also set values to any predefined functions

#define square(x) x*x main() { int i; i = 64/square(4); printf("%d",i); }

4 Answers   Google, HCL, Quick Heal, WTF,

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Cau u say the output....?

1 Answers  

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¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...

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