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main( )
{
int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}};
printf(“%u %u %u %d \n”,a,*a,**a,***a);
printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1);
}
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Answer / susie
Answer :
100, 100, 100, 2
114, 104, 102, 3
Explanation:
The given array is a 3-D one. It can also be viewed as a
1-D array.
2
4
7
8
3
4
2
2
2
3
3
4
100 102 104 106 108 110 112 114 116 118
120 122
thus, for the first printf statement a, *a, **a give
address of first element . since the indirection ***a gives
the value. Hence, the first line of the output.
for the second printf a+1 increases in the third dimension
thus points to value at 114, *a+1 increments in second
dimension thus points to 104, **a +1 increments the first
dimension thus points to 102 and ***a+1 first gets the value
at first location and then increments it by 1. Hence, the
output.
| Is This Answer Correct ? | 11 Yes | 17 No |
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C Code 
