Answer / rajesh

the answer is 8.if n fork calls then no.of processes will
be 2^n

Answer / nishant

7 child process will b created.
Because 1 process ia already present at the start

Answer / abhinav

The process creation at each fork is shown. the number after
fork tells which process is calling fork.
Total 8 processes.

/--1
/---fork1
/ \--5
/-fork1-
/ \ /--3
/ \---fork3
---fork1 \--6
\
| /--2
\ /--fork2--
\ / \--7
\fork2--
\ /--4
\--fork4--
\--8

Answer / rakesh

ya right 8 processes .
For further explanation visit - http://powerboom.blog.co.in

This site gives good explanation .

Answer / sh@n

When under a recursive call 2^n-1 else its 2^n.

Answer / ann

7

Answer / nisha

'8' as formulated by rajesh but in case, fork() used with the combination of && and || operators,,this formula doesn't work...

Answer / sagar arora

8 because of the rajesh logic but sometimes it fails.

How we will connect multiple client ? (without using fork,thread)

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main() { signed int bit=512, mBit; { mBit = ~bit; bit = bit & ~bit ; printf("%d %d", bit, mBit); } } a. 0, 0 b. 0, 513 c. 512, 0 d. 0, -513

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