Answer / susie

Answer :

0

Explanation:

After ‘ptr’ reaches the end of the string the value pointed
by ‘str’ is ‘\0’. So the value of ‘str’ is less than that of
‘least’. So the value of ‘least’ finally is 0.

What is wrong with the following code? int *foo() { int *s = malloc(sizeof(int)100); assert(s != NULL); return s; }

1 Answers  

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main(int argc, char *argv[]) { (main && argc) ? main(argc-1, NULL) : return 0; } a. Runtime error. b. Compile error. Illegal syntax c. Gets into Infinite loop d. None of the above

4 Answers   HCL, LG,

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main() { int i; printf("%d",scanf("%d",&i)); // value 10 is given as input here }

2 Answers   IBM,

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main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

1 Answers  

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main() { struct date; struct student { char name[30]; struct date dob; }stud; struct date { int day,month,year; }; scanf("%s%d%d%d", stud.rollno, &student.dob.day, &student.dob.month, &student.dob.year); }

1 Answers  

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Is the following code legal? struct a { int x; struct a *b; }

2 Answers  

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main() { int a=2,*f1,*f2; f1=f2=&a; *f2+=*f2+=a+=2.5; printf("\n%d %d %d",a,*f1,*f2); }

6 Answers  

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find simple interest & compund interest

2 Answers  

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#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d----%d",*p,*q); }

1 Answers  

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main() { extern out; printf("%d", out); } int out=100;

1 Answers  

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main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }

1 Answers  

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void ( * abc( int, void ( *def) () ) ) ();

1 Answers  

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