Answer / susie

Answer :

Compiler Error: Constant expression required in
function main.

Explanation:

The case statement can have only constant expressions (this
implies that we cannot use variable names directly so an error).

Note:

Enumerated types can be used in case statements.

Hi, i have a project that the teacher want a pyramid of numbers in C# or java...when we click a button...the pyramid should be generated in a listbox/or JtextArea...and the pyramid should have the folowing form: 1 232 34543 4567654 567898765 67890109876 7890123210987 890123454321098 90123456765432109 0123456789876543210 Plz help with codes...didn't find anything on the net.

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main() { printf("%d", out); } int out=100;

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write a function to give demostrate the functionality of 3d in 1d. function prototye: change(int value,int indexX,int indexY,int indexZ, int [] 1dArray); value=what is the date; indexX=x-asix indexY=y-axis indexZ=z-axis and 1dArray=in which and where the value is stored??

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#include<stdio.h> int main() { int a=3,post,pre; post= a++ * a++ * a++; a=3; pre= ++a * ++a * ++a; printf("post=%d pre=%d",post,pre); return 0; }

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main() { int i = 258; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }

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main() { unsigned int i=65000; while(i++!=0); printf("%d",i); }

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main() { int i=4,j=7; j = j || i++ && printf("YOU CAN"); printf("%d %d", i, j); }

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main() { int a[10]; printf("%d",*a+1-*a+3); }

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int aaa() {printf(“Hi”);} int bbb(){printf(“hello”);} iny ccc(){printf(“bye”);} main() { int ( * ptr[3]) (); ptr[0] = aaa; ptr[1] = bbb; ptr[2] =ccc; ptr[2](); }

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