func(a,b)
int a,b;
{
return( a= (a==b) );
}
main()
{
int process(),func();
printf("The value of process is %d !\n
",process(func,3,6));
}
process(pf,val1,val2)
int (*pf) ();
int val1,val2;
{
return((*pf) (val1,val2));
}
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Answer / susie
Answer :
The value if process is 0 !
Explanation:
The function 'process' has 3 parameters - 1, a pointer to
another function 2 and 3, integers. When this function is
invoked from main, the following substitutions for formal
parameters take place: func for pf, 3 for val1 and 6 for
val2. This function returns the result of the operation
performed by the function 'func'. The function func has two
integer parameters. The formal parameters are substituted as
3 for a and 6 for b. since 3 is not equal to 6, a==b returns
0. therefore the function returns 0 which in turn is
returned by the function 'process'.
| Is This Answer Correct ? | 5 Yes | 2 No |
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C Code 
