Answer / susie

Answer :

Explanation:

Here we have only one pointer to type char and since we take
input in the same pointer thus we keep writing over in the
same location, each time shifting the pointer value by 1.
Suppose the inputs are MOUSE, TRACK and VIRTUAL. Then for
the first input suppose the pointer starts at location 100
then the input one is stored as

M
O
U
S
E
\0
When the second input is given the pointer is incremented as
j value becomes 1, so the input is filled in memory starting
from 101.

M
T
R
A
C
K
\0
The third input starts filling from the location 102

M
T
V
I
R
T
U
A
L
\0
This is the final value stored .

The first printf prints the values at the position q,
q+1 and q+2 = M T V

The second printf prints three strings starting from
locations q, q+1, q+2

i.e MTVIRTUAL, TVIRTUAL and VIRTUAL.

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I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..

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