main()
{
void swap();
int x=10,y=8;
swap(&x,&y);
printf("x=%d y=%d",x,y);
}
void swap(int *a, int *b)
{
*a ^= *b, *b ^= *a, *a ^= *b;
}
Answers were Sorted based on User's Feedback
Answer / susie
Answer :
x=10 y=8
Explanation:
Using ^ like this is a way to swap two variables without
using a temporary variable and that too in a single statement.
Inside main(), void swap(); means that swap is a function
that may take any number of arguments (not no arguments) and
returns nothing. So this doesn’t issue a compiler error by
the call swap(&x,&y); that has two arguments.
This convention is historically due to pre-ANSI style
(referred to as Kernighan and Ritchie style) style of
function declaration. In that style, the swap function will
be defined as follows,
void swap()
int *a, int *b
{
*a ^= *b, *b ^= *a, *a ^= *b;
}
where the arguments follow the (). So naturally the
declaration for swap will look like, void swap() which means
the swap can take any number of arguments.
| Is This Answer Correct ? | 4 Yes | 0 No |
main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }
int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().
main() { int i=3; switch(i) { default:printf("zero"); case 1: printf("one"); break; case 2:printf("two"); break; case 3: printf("three"); break; } }
#include <stdio.h> int main(void) { int a=4, b=2; a=b<<a+b>>2 ; printf("%d",a); return 0; }
enum colors {BLACK,BLUE,GREEN} main() { printf("%d..%d..%d",BLACK,BLUE,GREEN); return(1); }
There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }
#include"math.h" void main() { printf("Hi everybody"); } if <stdio.h> will be included then this program will must compile, but as we know that when we include a header file in "" then any system defined function find its defination from all the directrives. So is this code of segment will compile? If no then why?
Give a one-line C expression to test whether a number is a power of 2.
print numbers till we want without using loops or condition statements like specifically(for,do while, while swiches, if etc)!
C program to print magic square of order n where n > 3 and n is odd
main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }
what will be the output of this program? void main() { int a[]={5,10,15}; int i=0,num; num=a[++i] + ++i +(++i); printf("%d",num); }