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#include<stdio.h>
main()
{
int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} };
int *p,*q;
p=&a[2][2][2];
*q=***a;
printf("%d..%d",*p,*q);
}
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Answer / susie
Answer :
garbagevalue..1
Explanation:
p=&a[2][2][2] you declare only two 2D arrays. but you are
trying to access the third 2D(which you are not declared) it
will print garbage values. *q=***a starting address of a is
assigned integer pointer. now q is pointing to starting
address of a.if you print *q meAnswer:it will print first
element of 3D array.
| Is This Answer Correct ? | 10 Yes | 1 No |
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C Code 
