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main()

{

int x=5;

for(;x!=0;x--) {

printf("x=%d\n", x--);

}

}

a. 5, 4, 3, 2,1

b. 4, 3, 2, 1, 0

c. 5, 3, 1

d. none of the above

Answers were Sorted based on User's Feedback



main() { int x=5; for(;x!=0;x--) { printf("x=%d\n", x--); } } ..

Answer / guest

d) Infinite loop as x is decremented twice, it never be 0

and loop is going on & on

Is This Answer Correct ?    13 Yes 0 No

main() { int x=5; for(;x!=0;x--) { printf("x=%d\n", x--); } } ..

Answer / ajit

first error in 4 step as syntax error
this is so that for(x!=0;x--) answer is d becoze here
not defined x=?

Is This Answer Correct ?    0 Yes 10 No

Post New Answer

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