Answer / pavan_mustyala

Hi, This code works for 4 digit numbers(may be with some
minor exceptions). But i am trying a generic approach and
shall update very soon with more nicer solution.
/*************/
#include
char *arr1[10] =
{"One","Two","Three","Four","Five","Six","Seven","Eight","Ni
ne", "Ten"};
char *arr2[10] =
{"Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen"
,"Seventeen","Eighteen","Nineteen"};
char *arr3[10] =
{"Ten","Twenty","Thirty","Fourty","Fifty","sixty","Seventy",
"Eighty","Ninety","Hundred"};
char *arr4[10] = {"Hundred","Thousand"};

int CountGlobal;

int func(int);
void printWord(int, int);

int main(int argc, char* argv[])
{
int num = 2022;
int temp = num;
int count = 0;

// First count the number of digits in the given
number
while(temp)
{
temp /= 10;
count++;
}

CountGlobal = count;

while(count && num)
{
num = func(num);
count--;
}

return 0;
}

// Functions to print digits in words
int func(int num)
{
int temp = num;
int count = 0;


while(temp > 9)
{
temp /= 10;
count++;
}

printWord(temp,count+1);

while(count)
{
temp *= 10;
count--;
}

return(num - temp);
}

void printWord(int num, int count)
{

switch(count)
{
case 0:
//printf("%s", arr[num-1]);
break;
case 1:
printf("%s", arr1[num-1]);
break;
case 2:
printf("%s ", arr3[num-1]);
//printf("%s ", arr3[1]);
break;
case 3:
printf("%s ", arr1[num-1]);
printf("%s ", arr4[0]);
break;
case 4:
printf("%s ", arr1[num-1]);
printf("%s ", arr4[1]);
break;
case 5:
//printf("%s", arr[num-1]);
break;
default:
break;
}
}
/**********/

Answer / vin

not sure wether this is the best in performance.
need to use switch case.

string = "";
for lengh of the number
{
switch(char)
{
case 1:
string = string + one;
case 2:
string = string + two;
case 3:
string = string + three;
}

{

but that gives only letters into numbers.
for ex 1043 will be onezerothreefour

this does not end here, please modify or add.

as this has to be transformed into numebrsystem

main() { char c; int i = 456; clrscr(); c = i; printf("%d", c); } a. 456 b. -456 c. random number d. none of the above

3 Answers   BrickRed, HCL,

---

main() { char a[4]="HELL"; printf("%s",a); }

3 Answers   Wipro,

---

how can i cast a char type array to an int type array

2 Answers  

---

main() { float me = 1.1; double you = 1.1; if(me==you) printf("I love U"); else printf("I hate U"); }

1 Answers  

---

Set up procedure for generating a wire frame display of a polyhedron with the hidden edges of the object drawn with dashed lines

0 Answers   IBM,

---

struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }

1 Answers  

---

#define DIM( array, type) sizeof(array)/sizeof(type) main() { int arr[10]; printf(“The dimension of the array is %d”, DIM(arr, int)); }

1 Answers  

---

main() { char *p = “ayqm”; printf(“%c”,++*(p++)); }

29 Answers   IBM, TCS, UGC NET, Wipro,

---

how to delete an element in an array

2 Answers   IBM,

---

# include<stdio.h> aaa() { printf("hi"); } bbb(){ printf("hello"); } ccc(){ printf("bye"); } main() { int (*ptr[3])(); ptr[0]=aaa; ptr[1]=bbb; ptr[2]=ccc; ptr[2](); }

1 Answers  

---

why java is platform independent?

13 Answers   Wipro,

---

main() { int *ptr=(int*)malloc(sizeof(int)); *ptr=4; printf("%d",(*ptr)+++*ptr++); }

3 Answers   GNITC,

---