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A can do a piece of work in 90 dAYS ,B in 40 days and C
in 12 days .they work for a day each in turn ,ie, first day
A does it alone ,B does it in the second day and C the
third day . after that A does it for another day and so
on . after finishing the work they get rs. 240. if the
wages are divided in proportion to the work done by
them ,find what each will get .. (********* PLEASE GIVE
THE EXPLANATION*****)
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Answer / kathir
ratio of their work is 12:27:81
so the amounts are 24,54,162
| Is This Answer Correct ? | 19 Yes | 2 No |
Answer / saikat
in 1 day A does 1\90 th of the job, B 1\ 40th and C 1\12th.
At the end of 3 days total work done by all three will be 43
\360. So it takes about 8 days for each of them to complete
the work before the last day. On the ladt day, A works for
1 day, B for .11 days and C doesn't work at all. So the
ratios of work done by the are -- .1:.2:.67, where total
reimbusement is Rs. 240. So, A should get Rs.24, B Rs. 48 C
Rs. 160.
| Is This Answer Correct ? | 7 Yes | 5 No |
Answer / navin
if t ended with C working on d last day.. all o'them have
worked 4 equal no. of days... so they share t equally,
i.e, Rs.80 each...
| Is This Answer Correct ? | 3 Yes | 8 No |
Answer / srivatsan
Rs170 for C , Rs51 for B , Rs 19 for A.
Its general maths and I'm not too confident about the answer.
Its correct but isn't accurate. Rounded off figure.
| Is This Answer Correct ? | 2 Yes | 8 No |
Answer / swapna
Work done by each is
a/90,b/40,c/12
so 4a:9b:30c=240
so a=22.60
b=50.85
c=169.5
| Is This Answer Correct ? | 2 Yes | 9 No |
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