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What is the remainder left after dividing 1! + 2! + 3! + ? +
100! By 7?
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Answer / guest
A tricky one.
7! onwards all terms are divisible by 7 as 7 is one of the
factor. So there is no remainder left for those terms i.e.
remainder left after dividing 7! + 8! + 9! + ... + 100! is 0.
The only part to be consider is
= 1! + 2! + 3! + 4! + 5! + 6!
= 1 + 2 + 6 + 24 + 120 + 720
= 873
The remainder left after dividing 873 by 7 is 5
Hence, the remainder is 5.
| Is This Answer Correct ? | 83 Yes | 3 No |
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