2 vessels A and B contain spirit and water in the ratio of
5:2 and 7:6 respectively .find the ratio in which these
mixtures be mixed 2 obtain a new mixture in the vessel
containg spirit and water in the ratio 8:5
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Step (i) : Let C.P. of spirit be Re.1
Given ratio of mixture in A = 5:2
spirit in 1 lit mixture in A = 5/7 lit
C.P of 1 lit mixture in A = Rs. 5/7
Ratio of Mixture in B = 7:6
spirit in 1 litre mixture in B – 7/13 lit
C.P of 1 lit mixture in B = Rs. 7/13
Ratio of new mixture = 8:5
spirit in 1 lit mixture = 8/13
C.P of 1 lit mixture = Rs. 8/13 (Mean price)
Step (ii) : By the rule of allegation,
i. C.P of 1 liter of mixture in A =5/7
ii. C.P of 1 liter of mixture in B = 7/13
iii. Mean price (p) = 8/13
iv. d – m = 5/7 – 8/13 = 9/91
v. m – c = 8/13 – 7/13 = 1/13
Required ratio = 2/91 : 1/13 = 9:7
| Is This Answer Correct ? | 19 Yes | 3 No |
Answer / saravanan p
Let us Consider
First Vessel A Contains 5ml:2ml
second Vessel B Contains 7ml:6ml
when we add these two we get 12ml:8ml (i.e) 3:2
when we add 20ml:12ml ratio of mixture we will
get 8:5 ratio...
| Is This Answer Correct ? | 9 Yes | 7 No |
just a correction in calculation to my previous post
Required ratio = 9/91 : 1/13 = 9:7
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / lubhanshee
A → 5 : 2 = 7 ×13
B → 7 : 6 = 13 ×7
Resultant→ 8 : 5 = 13 ×7
A B
65 49
/
56
/
7 9
THE RATIO IS 7:9
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / mackdeeps
Let us Consider
First Vessel A Contains 5ml:2ml
second Vessel B Contains 7ml:6ml
when we add these two we get 12ml:8ml (i.e) 3:2
If we consider that 3 is 12ml then 8 is how much?
8*12/3 = 32 we get
same way
If we consider that 2 is 8ml then 5 is how much?
5*8/2 = 20 we get
So the new mixture is 32:20 to get ratio 8:5
| Is This Answer Correct ? | 0 Yes | 7 No |
Answer / nanthu irtt
let us take 5x:2x and 7y:6y
so 5x+7y=8
2x+6y=5 to solve this we get x=19/40
y=7/16 take lcm we get
ratio 35:38........... if it is correct contact through
phone +919486138241
| Is This Answer Correct ? | 4 Yes | 21 No |
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