Answer / metodija pankovski

Hi all i read all answers and in every answer you have some mistake.IT ask how many subnets and how many hosts have per subnet not how many host have totally!
So here is the most logical and easy understanding of sub-netting with out need to convert to binary we all know to make binary no. from the regular number.
23 subnet mask =255.255.254.0
27 subnet mask =255.255.255.224
it ask for 27 how many subnets will have and how many hosts
so we start
we all should know that totally in subnet mask have 32-bits here first 27 are taken for the subnet mask so we left 5 bits for host 32-27=5
number of the host we get from formula
2^n-2=No of host per subnet
so we get
2^5-2=32-2=30
we take 2 address for the broadcast and subnet thats why is 2^n-2
We finish with the hosts
no lets get the no. of subnets
first given was /23 bits and the second was /27-bits
we just do this
27-23=4
no. of subnet is 2^n we don`t have here -2!!! some one make mistake in the answers so remember you don`t take minus 2 when you solve no. of subnets thats for hosts!!
so
27-23=4
2^4=16
ANSWER OF THE QUESTION IS:
Subnets 16
HOST 30 per subnet
address range like this
172.17.32.0 first subnet
172.17.32.32
172.17.32.64
172.17.32.96
172.17.32.128
172.17.32.160
172.17.32.192
172.17.32.224
172.17.33.0
172.17.33.32
172.17.33.64
172.17.33.96
172.17.33.128
172.17.33.160
172.17.33.192
172.17.33.224 last one
I hope i help to some of you:)
THIS IS TE REAL ANSWER!

Answer / jitendera kumar sinha

172.17.32.0/23
mask of that ip is
sunated in the
172.17.32.0/27
sunating of 4 bit
total number of n/w
2^4-2=14(according to cisco)
now taol nomber of valabe bit for host is 16-11=5
so taotal nomber of avilable host is 2^5-2=30
note**(why eleven is redused from 16.ans becoz this is a
xlass b adress and it have 16 bit for n/w and 16 bit for
host but we have the mask of 27 then we have taken 11 bit
from host for n/w.so we redused that eleven bit from the 16)
now
now hat is the mask of that ip
255.255.128+64+32+16+8+4+2+1.128+64+32
i.e
mask is 255.255.255.224/27
so the block size is 256-224=32
so the n/w is
172.17.32.0---------------------.31
.32------------------------------.63 and so on

Answer / not_a_dum-ass

omg, you ppl just confuse the hell out of yourselves don't
you?

very simple question:
how many subnets can be GAINED / how many USABLE hosts per
subnet......

16 subnets GAINED
30 USABLE host adresses per

Answer / suraj kumar gupta

172.17.32.0/23 into a /27 how many subnet?

n=23-27=4


total no subnet mask =2^n - 2=2^4=16

where n is the no host

subnet =2^n=2^4=16

Total no. of usable host are..... 30


We have used the subnet bit so remainig bits are for host
means...


5 bits are available...


so 2 to the power 5


means 32 total no. of hosts..


usable hosts are..32-2 ====30 answer

Answer / megadeth

as explained earliar if you go by the cisco way. remember
you dont need to do any such calculations in such
problems,even vlsm and supernetting.

you generally remember /27 tends to 32 hosts per subnet
/25 tends to 128 similarly you can figure out the rest of it

Answer / devender chauhan

There is 16 subnet being made when we extend /23 to /27.
Because we are using 4 bits from host bits.

2*2*2*2 = 16


so the subnets are :-

172.17.32.0 to 172.17.47.0

Thanks

Answer / robert davenport

I have one bit of clarification on my answer. As the IP
address of, 172.17.32.0, was given that will reduce the
amount of subnets. The third octet (.32.) has restricted us
to one subnet on the /23 prefix. so that will change the
total subnets for the /27, see the following:

Prefix Subnets in Hosts per
Length Range Given Subnet
/23 1 510
/27 14 30

So, the Subnets will increase by 13 and the hosts will drop
to 420 (14x30). Hope I got it this time.

Answer / devender chauhan

There is 16 subnet being made when we extend /23 to /27.
Because we are using 4 bits from host bits.

2*2*2*2 = 16


so the subnets are :-

172.17.32.0 to 172.17.32.31

172.17.32.32 to 172.17.32.63

and continue...with 32 IPs per subnet...

Answer / bhisham

172.17.32.0/23 into a /27 how mant subnet?

n=23-27=4

total no subnet mask =2^n - 2=2^4-2=14
where n is the no host
host =2^n-2=14
subnet =2^n=2^4=16

Answer / devender chauhan

There is 16 subnet being made when we extend /23 to /27.
Because we are using 4 bits from host bits.

2*2*2*2 = 16


so the subnets are :-

172.17.32.0 to 172.17.47.0


and the total number of host is 16x255 =4080 host

What is a characteristic of Store and Forward switches? A.) They forward the frame before it is completely read. B.) They work at wire speed. C.) They are the same a Cut-Through switching. D.) They read the entire frame and check CRC before forwarding. E.) They decrease latency.

1 Answers  

What is Cisco register bits? How they help?

1 Answers   jetking,

Which layer defines bit synchronization? A.) Application B.) Network C.) Transport D.) Physical E.) Session F.) Session

2 Answers  

Which command switches from User mode to Privileged mode? A.) login B.) privilege C.) admin D.) enable E.) enter F.) root

5 Answers  

whats the routing protocol supporting in both juniper , cisco routers.

10 Answers   HCL,

IP standard access lists use which of the following as a basis for permitting or denying packets? A.) destination address B.) port C.) protocol D.) source address

2 Answers  

What is the purpose of Split Horizon? A.) It prevents the regular update messages from reinstating a route that has gone down B.) Information received on an interface cannot be sent back out the same interface C.) Informs all neighbor routers that two routes exist D.) Tells the router the destination is unreachable

1 Answers  

What is the default IPX Ethernet encapsulation? A.) SNAP B.) Arpa C.) 802.2 D.) Novell-Ether E.) SAP

2 Answers  

How do areas benefit a link state inter network?

1 Answers  

friends i have some problem in the acess list plz help me out. purbi sinha. 1 what is the diffrence b/w inbound and out bound access list 2 what is main diffrence betwwen standred acesslist and extended access list 3 where should i keep stnadred access list and exatended access list i mean at which interface and why? 4 why wild card masking is used 5 what is switch febric in switching plz help me out i am litle bit confuse

1 Answers  

Given the Novell IPX address 1aceb0b.0000.0c12.3456 which part is the network portion of the address? A.) 0000 B.) 1 C.) 3456 D.) 1ace E.) 0000.0c12.3456 F.) 1aceb0b

2 Answers  

what is Bandwidth capping

1 Answers   Infosys,