How many subnets can be gained by subnetting 172.17.32.0/23
into a /27 mask, and how many usable
host addresses will there be per subnet?
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Answer Posted / metodija pankovski
Hi all i read all answers and in every answer you have some mistake.IT ask how many subnets and how many hosts have per subnet not how many host have totally!
So here is the most logical and easy understanding of sub-netting with out need to convert to binary we all know to make binary no. from the regular number.
23 subnet mask =255.255.254.0
27 subnet mask =255.255.255.224
it ask for 27 how many subnets will have and how many hosts
so we start
we all should know that totally in subnet mask have 32-bits here first 27 are taken for the subnet mask so we left 5 bits for host 32-27=5
number of the host we get from formula
2^n-2=No of host per subnet
so we get
2^5-2=32-2=30
we take 2 address for the broadcast and subnet thats why is 2^n-2
We finish with the hosts
no lets get the no. of subnets
first given was /23 bits and the second was /27-bits
we just do this
27-23=4
no. of subnet is 2^n we don`t have here -2!!! some one make mistake in the answers so remember you don`t take minus 2 when you solve no. of subnets thats for hosts!!
so
27-23=4
2^4=16
ANSWER OF THE QUESTION IS:
Subnets 16
HOST 30 per subnet
address range like this
172.17.32.0 first subnet
172.17.32.32
172.17.32.64
172.17.32.96
172.17.32.128
172.17.32.160
172.17.32.192
172.17.32.224
172.17.33.0
172.17.33.32
172.17.33.64
172.17.33.96
172.17.33.128
172.17.33.160
172.17.33.192
172.17.33.224 last one
I hope i help to some of you:)
THIS IS TE REAL ANSWER!
| Is This Answer Correct ? | 51 Yes | 3 No |
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