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WHAT HAPPENS WHEN SQUARE PULSE IS GIVEN TO THE INPUT OF THE
TRANSFORMER
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Answer / lokesh
It is also a A.C SIGNAL so output goes to a square pulse
| Is This Answer Correct ? | 17 Yes | 11 No |
Answer / sanket patil
IN SOME CASES THE TRANSFORMER IS DESIGNED TO APPLY DC
PULSE( NOT CONTINUOUS DC SIGNAL ) TO ITS PRIMARY WINDING
AND THE TRANSFORMER IS CALLED AS "PULSE TRANSFORMER".
IF DC VOLTAGE IS GIVEN TO WDG; AS WDS IS AS GOOD AS
INDUCTOR HENCE CURRENT I=(1/L)*INTEGRAL(Vdc)dt, WHICH WILL
CONTINUOUSLY INCREASE THE CURRENT FLOWING THROUGH THE
WINDING. HENCE THE WIDTH OF THE PULSE SHOULD BE SMALL
OTHERWISE THE TRANSFORMER WINDING WILL BURN.
IN THE PULSE TRANSFORMERS THE RESISTANCE OF THE WINDING
SHOULD BE KEPT MINIMUM TO LINIT THE I^2*R LOSSES AND LIMIT
THE TEMP OF THE WINDING BEFORE INSULATION FAILURE.
| Is This Answer Correct ? | 7 Yes | 2 No |
Answer / sateesh
if the freequency is high we will get same square wave with
modified magnitude but if the freqcency is low impulse will
appiare
| Is This Answer Correct ? | 10 Yes | 6 No |
Answer / ashok
what will be width of pulse and min voltage needed for
transformation.
| Is This Answer Correct ? | 4 Yes | 1 No |
In Transformer secondary the emf induced depends on the
rate of change of flux,If square pulse or pulsating DC is
given thn output will be triangular wave(due to inductnce
of secondary)
| Is This Answer Correct ? | 7 Yes | 5 No |
Answer / sirin dutta chowdhury
Induced voltage=4.44*f*N*A*B = 4*form factor*f*N*A*B
f=freq
N=no of primary turns
A=area of wdg
B=max flux density
For sinusoidal input, form factor= 1.1 , its a peaky wave
form
But for square ac input signal, form factor is less than
1.1. (as its non peaky)
So other factors remaining same, induced voltage decreases
for square input ac signal.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / ashok jain
It depends on the width of pulse,otherwise transformer will
go in saturation.also at secondary the pulse will not be
simple pulse but it will be rather impulse.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / kuldip
Depends on the type of the input given, wheather current or
voltage .
If its a current waveform then considering the changes in
emf on the primary side to the induced emf on the sec side,
it will go phase changes to result the output in the form
of ramp & slope resulting in the triangular waveform.
Considering the voltage waveform we receive output in the
form of impulse waves or square waves with reduced widths.
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / anil
if it is current input than answer is triangular voltage
if input is voltage than output is pulse but may not be a
square but out of phase
| Is This Answer Correct ? | 1 Yes | 3 No |
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