Answer / alok kumar

initially there were 18 bullets.
each person had 6 bullets.
after firing 4 bullets remaining were 2 each and the sum is
6,which was initially each one's share

Answer / soumyajeet sarangi

let the no of bullets each hav be x
then after firing 4 bullets
each hav x-4 bullets
so,x-4+x-4+x-4=x
3x-12=x;
x=6
so the number of bullets each hav is 6.
3 persons mens 3*6=18
the total number of bullets is 18(ans)

Answer / satya.tivari

6.
each of them shared 4 bullets and the remaining bullets are
2 of each which is equal to initial count.

Answer / beatrice

initially they had 18 bullets which was equally partitioned
among 3 of them the share was given to each of the three
and each of thenm used 4 bullets from their share so the
remainin is 2 in each share and the sum wud bring 6(2+2+2)
and this was the individual share given to each so again
the sum brings 18(6+6+6).so 18 is the answer

Answer / prasun bose

Let the initial number of bullets be 'a'
then by question each got a/3 bullets as share
when 4 bullets fired means each had (a/3)-4
by question when 3 ppl added it comes 3{(a/3)-4}
and again by question this is equal to a/3 initial
share
by solving a/3=3{(a/3)-4}
we have a/3= (3a/3)-12
or, 12= a-(a/3) by shifting sides
or, 12= 2a/3
or, 36= 2a by cross multiplication
or, 18=a
Thus the initial number of bullet was 18

Answer / sairam

Ans.6
let initial number of bullets be 3x.
therefore each one has share of x bullets.
total number of bullets fired=3*4=12.
given that sum of remaining bullets are equal to the initial
share each had got=x.
therefore we have equation
12+x=3x.
12=2x.
x=6

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