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fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
}
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Answer / shilpa m
Right answer is 0.
fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d\n", x);
}
Here if fun(10)is called the sequence goes as fun(10)->fun
(5)->fun(2.5)->fun(1.25)->fun(0.625) after this itself
printf will be executed and 0 is printed.
please expalin how answer is 0 1 2 5 10 is right answer???
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / enigma
Strictly speaking the answer is undefined until someone forces the output text from the console buffer to the screen.
Otherwise it would normally print 012510
Debug it inside MSVC and witness no output. In reality though most implementations will do a final flush to screen....
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / mortal
it will print "0" i.e zero since compiler wont get to the
print statement until the value is zero.
| Is This Answer Correct ? | 2 Yes | 5 No |
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